
Из пункта А и В одновременно навстречу друг другу выехали два велосипедиста через 24 мин они
встретились через 36 мин после встречи велосипедист выехавший из пункта А прибыл в пункт В сколько времени затратит на весь путь велосипедист выехавший из пункта в ? А 19 мин В 43 мин С 46 мин D 40 мин

Ответы на вопрос




Problem Analysis
Two cyclists start simultaneously from points A and B and meet after 36 minutes. One of the cyclists arrives at point B after 19 minutes. We need to determine how long it will take the cyclist who started from point B to complete the entire journey.
Solution
Let's assume the distance between points A and B is d.
We know that the two cyclists meet after 36 minutes. This means that the cyclist who started from point A traveled for 36 minutes, while the cyclist who started from point B traveled for 36 minutes minus the time it took for the cyclist from point A to reach point B.
We also know that the cyclist from point A arrived at point B after 19 minutes. This means that the cyclist from point B traveled for 36 minutes minus 19 minutes to reach the meeting point.
To find the time it will take for the cyclist from point B to complete the entire journey, we need to add the time it took for the cyclist from point B to reach the meeting point to the time it will take for the cyclist from point B to travel from the meeting point to point A.
Let's calculate the time it will take for the cyclist from point B to complete the entire journey.
Calculation
The time it took for the cyclist from point B to reach the meeting point = 36 minutes - 19 minutes = 17 minutes.
The time it will take for the cyclist from point B to travel from the meeting point to point A is equal to the time it took for the cyclist from point A to travel from point A to point B, which is 36 minutes.
Therefore, the total time it will take for the cyclist from point B to complete the entire journey is 17 minutes + 36 minutes = 53 minutes.
Answer
The cyclist who started from point B will take 53 minutes to complete the entire journey.


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