Question

Vichisli perimetr i ploshad pryamougolnika so storonoe 6dm i 4dm ikvadrata so storonoe 5dm sravni perimetri etih figur asatem ih ploshadi

Answer 1

Прямоугольник:
S=6*4=24дм
P=2(6+4)=20дм
квадрат:
S= 5*5=25дм
P=2(5+5)=20дм
Периметры равны 

Answer 2

Calculating the Perimeter and Area of Rectangles

To calculate the perimeter and area of a rectangle with sides of 6 dm and 4 dm, and another rectangle with sides of 5 dm, we can use the following formulas:

Perimeter of a rectangle: The perimeter of a rectangle is calculated by adding the lengths of all its sides. For a rectangle with sides of length L and width W, the perimeter (P) is given by the formula: \[ P = 2L + 2W \]

Area of a rectangle: The area of a rectangle is calculated by multiplying its length and width. For a rectangle with sides of length L and width W, the area (A) is given by the formula: \[ A = L \times W \]

Calculating the Perimeter and Area of the First Rectangle

The first rectangle has sides of 6 dm and 4 dm.

Perimeter: \[ P = 2 \times 6 \, \text{dm} + 2 \times 4 \, \text{dm} = 12 \, \text{dm} + 8 \, \text{dm} = 20 \, \text{dm} \]

Area: \[ A = 6 \, \text{dm} \times 4 \, \text{dm} = 24 \, \text{dm}^2 \]

Calculating the Perimeter and Area of the Second Rectangle

The second rectangle has sides of 5 dm.

Perimeter: \[ P = 2 \times 5 \, \text{dm} + 2 \times 5 \, \text{dm} = 10 \, \text{dm} + 10 \, \text{dm} = 20 \, \text{dm} \]

Area: \[ A = 5 \, \text{dm} \times 5 \, \text{dm} = 25 \, \text{dm}^2 \]

Comparing the Perimeters and Areas

The perimeters of both rectangles are 20 dm. The areas of the rectangles are 24 dm^2 and 25 dm^2 for the first and second rectangles, respectively.

In conclusion, while the perimeters of the two rectangles are the same, the area of the second rectangle (25 dm^2) is slightly larger than the area of the first rectangle (24 dm^2).