Question

Первый вертолет пролетел 480 км.,а второй 800 км. Первый вертолет был в полете на 2 часа меньше чем второй. Сколько часов был в полете каждый вертолет если их скорости были одинаковыми?

Answer 1

1) 800-480=320(км)-на столько км больше полетел 2-ой за 2 часа. 2) 320:2=160 (км/час)- скорость вертолётов.
3)480:160=3 (часа)-был в полёте 1-й вертолёт.
4)800:160 =5 (часов)-был в полёте 2-ой вертолёт.

Answer 2

Problem Analysis

We are given two helicopters, where the first helicopter flew a distance of 480 km and the second helicopter flew a distance of 800 km. The first helicopter was in flight for 2 hours less than the second helicopter. We need to determine how many hours each helicopter was in flight if their speeds were the same.

Solution

Let's assume the speed of each helicopter is v km/h. We can use the formula distance = speed × time to solve this problem.

For the first helicopter: - Distance = 480 km - Time = t hours (unknown)

For the second helicopter: - Distance = 800 km - Time = t + 2 hours (since the first helicopter was in flight for 2 hours less than the second helicopter)

Using the formula, we can set up the following equations:

1. For the first helicopter: 480 = v × t2. For the second helicopter: 800 = v × (t + 2) To solve this system of equations, we can use substitution or elimination. Let's use substitution:

From equation 1, we can express t in terms of v: t = 480 / v

Substituting this value of t into equation 2, we get: 800 = v × (480 / v + 2)

Simplifying the equation: 800 = 480 + 2v

Rearranging the equation: 2v = 800 - 480 2v = 320 v = 320 / 2 v = 160

Now that we have the value of v, we can substitute it back into equation 1 to find the value of t: 480 = 160 × t t = 480 / 160 t = 3

Therefore, the first helicopter was in flight for 3 hours and the second helicopter was in flight for 5 hours.

Answer

If the speeds of the two helicopters were the same, the first helicopter was in flight for 3 hours and the second helicopter was in flight for 5 hours.