Question

Составь выражение:Волк и заяц соревновались в беге. Волк пробежал за 8 минут с метров, а заяц за 3 минуты пробежал 5/9 этого расстояния. На сколько скорость зайца оказалась больше скорости волка?

Answer 1

(5/9*С)/3 - С/8 = Х, где х - скорость зайца

Answer 2

5/9• с: 3- с:8=5/27 с-с/8

Answer 3

Problem Analysis

We are given that a wolf and a hare are competing in a race. The wolf completes a certain distance in 8 minutes, while the hare completes 5/9 of that distance in 3 minutes. We need to determine by how much the hare's speed is greater than the wolf's speed.

Solution

To solve this problem, we need to compare the speeds of the wolf and the hare. Speed is defined as the distance traveled divided by the time taken. Let's calculate the speeds of the wolf and the hare and find the difference.

Let's assume the total distance is D.

The wolf completes the distance in 8 minutes, so its speed is D/8.

The hare completes 5/9 of the distance in 3 minutes, so its speed is (5/9)D/3.

To find the difference in speed, we subtract the wolf's speed from the hare's speed:

(5/9)D/3 - D/8

To simplify this expression, we need to find a common denominator for the fractions. The least common multiple of 9 and 8 is 72, so we can rewrite the expression as:

(40/72)D - (9/72)D

Simplifying further, we have:

(40D - 9D)/72

The difference in speed is:

31D/72

Therefore, the hare's speed is greater than the wolf's speed by 31D/72.

Answer

The hare's speed is 31D/72 greater than the wolf's speed.

Note: The value of D is not provided in the question, so we cannot determine the exact difference in speed without this information.