Question

Автобус и грузовая машина, скорость которой на 20 км/ч больше скорости автобуса, выехали одновременно навстречу друг другу из двух городов, расстояние между которыми 710 км. Найди скорости автобуса и грузовой машины, если известно, что они встретились через 5 ч. после выезда.

Answer 1

5*(х+х+20)=710
10х=710-100
10х=610
х=610/10
х=61 км/ч автобуса
61+20=81 км/ч грузовика

Answer 2

Problem Setup

Two vehicles, a bus and a truck, set off from two different cities towards each other. The truck's speed is 20 km/h faster than the bus's speed. The distance between the cities is 710 km. They meet each other 5 hours after departure.

Solution

Let's denote the speed of the bus as x km/h and the speed of the truck as (x + 20) km/h.

The total distance traveled by both vehicles is 710 km, and they meet after 5 hours. We can use the formula distance = speed × time to set up an equation.

The bus travels a distance of 5x km in 5 hours, and the truck travels a distance of 5(x + 20) km in the same time.

Equating the sum of their distances to the total distance between the cities gives us the equation: 5x + 5(x + 20) = 710

Solving this equation will give us the speed of the bus and the truck.

Calculation

Let's solve the equation: 5x + 5(x + 20) = 710

Expanding and simplifying: 5x + 5x + 100 = 710 10x + 100 = 710 10x = 710 - 100 10x = 610 x = 61

So, the speed of the bus is 61 km/h and the speed of the truck is (61 + 20) = 81 km/h.

Therefore, the speed of the bus is 61 km/h and the speed of the truck is 81 km/h.