Question

Решите уравнение, пожалуйста :)

Answer 1

4(1-cos4x)²/4+3cos4x-1=0
1-2cos4x+cos²4x+3cos4x-1=0
cos4x+cos²4x=0
cos4x(1+cos4x)=0
cos4x=0⇒4x=π/2+πk⇒x=π/8+πk/4,k∈z
cos4x=-1⇒4x=π+2πn⇒x=π/4+πn/2,n∈z

Answer 2

4sin⁴2x+3cos4x-1=0
4(1-cos4x)²/4+3cos4x-1=0
1-2cos4x+cos²4x+3cos4x-1=0
cos4x+cos²4x=0
cos4x(1+cos4x)=0
cos4x=0             или           cos4x=-1
4x=П/2+Пn                         4x=П+2Пm  
x=П/8+Пn/4,n ∈ Z               x=П/4+Пm/2,m ∈ Z
Ответ:П/8+Пn/4, П/4+Пm/2, n,m ∈ Z

Answer 3

Solving the Equation

To solve the equation, we need to determine the value of the variable that satisfies the equation. Unfortunately, the equation you provided is not clear. It seems to be incomplete or contains some formatting issues. Could you please provide the equation again, ensuring that it is properly formatted? This will allow me to provide you with an accurate solution.