Вопрос задан 17.02.2019 в 15:04. Предмет Математика. Спрашивает Бондар Лера.

(1 2/9-1 7/12)*5 7/13+(1 2/9+1 7/12):1 44/54=1/2 (РЕШЕНИЕ.СРОЧНО)

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Отвечает Грудницкий Василий.

1)1 2/9-1 7/12=11/9-19/12=88-114/72=-26/72=-13/36
2)-13/36*5 7/13=-13/36*72/13=-2
3)1 2/9+1 7/12=11/9+19/12=88+114/72=202/72=2 29/36
4)2 29/36:1 44/54=101/36*54/98=1 107/196
5)-2+1 107/196=-2+303/196=-89/196

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Давайте начнем с раскрытия скобок в выражении (1+2/9-1+7/12)*5+7/13+(1+2/9+1+7/12):1+44/54=1/2.

1. (1+2/9-1+7/12)*5 = (1+2/9-1+7/12)*5 = (1-1)+(2/9+7/12)*5 = (2/9+7/12)*5 = (8/36+35/36)*5 = (43/36)*5 = 215/36

2. (1+2/9+1+7/12):1 = (1+2/9+1+7/12):1 = (2+2/9+7/12) = (18/9+2/9+7/12) = (20/9+7/12) = (240/108+63/108) = 303/108 = 101/36

3. 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