Question

Пожалуйста помоги решить задачу .4класс ФГОС тетрадь стр 46 №79 №79 Реши задачи. Вычисли и запиши ответы. 1) Швейная мастерская изготовляет 15 штор за 2 ч. Сколько штор сможет изготовить мастерская за 8 ч? 2) ПЕРВАЯ БРИГАДА ВЫПОЛНЯЕТ 16КВ.М КИРПИЧНОЙ КЛАДКИ ЗА 8 ч,вторая - 12кв .м кладки за 4 ч. За сколько часов выполнят 55 кв. м кладки две бригады ,работая одновременно.

Answer 1

1.
1)8:2=4
2)15*4=60

2.
1)16:8=2
2)12:4=3
3)2+3=5
4)55:5=11

Answer 2

Task 1: Calculating the Number of Curtains Produced

To solve this problem, we can use the concept of proportionality. We know that the sewing workshop produces 15 curtains in 2 hours. We need to find out how many curtains it can produce in 8 hours.

Let's calculate it step by step.

Step 1: Calculate the workshop's productivity per hour. - Workshop's productivity per hour = 15 curtains / 2 hours - Workshop's productivity per hour = 7.5 curtains/hour

Step 2: Use the productivity per hour to find the total number of curtains produced in 8 hours. - Total curtains produced = Productivity per hour × Total hours - Total curtains produced = 7.5 curtains/hour × 8 hours - Total curtains produced = 60 curtains

So, the sewing workshop can produce 60 curtains in 8 hours.

Task 2: Calculating the Time for Two Brigades to Complete Masonry Work

In this task, we have two brigades working simultaneously, and we need to find out how long it will take them to complete a certain amount of masonry work.

Let's proceed with the solution.

Step 1: Calculate the combined productivity of both brigades per hour. - Productivity of the first brigade = 16 sq.m / 8 hours - Productivity of the first brigade = 2 sq.m/hour - Productivity of the second brigade = 12 sq.m / 4 hours - Productivity of the second brigade = 3 sq.m/hour - Combined productivity of both brigades = 2 sq.m/hour + 3 sq.m/hour - Combined productivity of both brigades = 5 sq.m/hour

Step 2: Use the combined productivity to find the time required to complete 55 sq.m of masonry work. - Time required = Total work / Combined productivity - Time required = 55 sq.m / 5 sq.m/hour - Time required = 11 hours

Therefore, the two brigades, working simultaneously, will complete 55 sq.m of masonry work in 11 hours.

I hope this helps! If you have any more questions or need further assistance, feel free to ask.