Question

6y-5x=58 2x-5y=-38,8 Пасибки заранее

Answer 1

1ое уравнение домножаем на 2, получаем
12y-10x=116
2ое уравнение домножаем на 5, получаем
10x-25y=-194

складываем уравнения, получаем
13y=-78
y=-6

Answer 2

Solving the System of Equations

To solve the system of equations 6y - 5x = 58 and 2x - 5y = -38, we can use the substitution method or the elimination method. Let's use the elimination method to solve this system of equations.

First, we'll multiply the second equation by 6 and the first equation by 2 to make the coefficients of x in both equations equal and then eliminate x.

Multiplying the second equation by 6: 12x - 30y = -228 [[8 #]]

Multiplying the first equation by 2: 12y - 10x = 116 [[8 #]]

Now, we'll add the two equations together to eliminate x: 12x - 30y + 12y - 10x = -228 + 116 2x - 18y = -112

Now, we can solve for y: -18y = -112 - 2x y = (112 + 2x) / 18

Next, we'll substitute the value of y into one of the original equations to solve for x. Let's substitute it into the second equation 2x - 5y = -38.

Substituting the value of y: 2x - 5((112 + 2x) / 18) = -38 2x - (560 + 10x) / 18 = -38 36x - 560 - 10x = -684 36x - 10x = -684 + 560 26x = -124 x = -124 / 26 x = -4.7692

Now that we have the value of x, we can substitute it back into the equation 6y - 5x = 58 to solve for y.

Substituting the value of x: 6y - 5(-4.7692) = 58 6y + 23.846 = 58 6y = 58 - 23.846 6y = 34.154 y = 34.154 / 6 y = 5.6923

So, the solution to the system of equations 6y - 5x = 58 and 2x - 5y = -38 is: x ≈ -4.7692 y ≈ 5.6923