Question

Первый вертолет пролетел 480 км. , а второй 800 км. первый вертолет был в полете на 2 часа меньше, чем второй. сколько часов был в полете каждый вертолет, если их скорости были одинаковыми?

Answer 1

(800-480):2=160(км/ч) скорость вертолёта.
480:160=3(ч) был в пути первый вертолёт.
800:160=5(ч) был в пути второй вертолёт.
Ответ: 3часа, 5часов.
поставь пожалуйста спасибо

Answer 2

Problem Analysis

We are given two helicopters that flew different distances. The first helicopter flew 480 km, while the second helicopter flew 800 km. The first helicopter was in the air for 2 hours less than the second helicopter. We need to determine how many hours each helicopter was in the air, assuming they had the same speed.

Solution

Let's assume the speed of both helicopters is x km/h.

We can use the formula: distance = speed × time to find the time each helicopter was in the air.

For the first helicopter: - Distance = 480 km - Speed = x km/h - Time = unknown (let's call it t1)

For the second helicopter: - Distance = 800 km - Speed = x km/h - Time = unknown (let's call it t2)

We also know that the first helicopter was in the air for 2 hours less than the second helicopter. So we can write the equation: t1 = t2 - 2.

Now, let's solve the equations to find the values of t1 and t2.

Calculation

From the equation distance = speed × time, we can rearrange it to solve for time: - For the first helicopter: t1 = distance / speed - For the second helicopter: t2 = distance / speed

Substituting the given distances and speeds: - For the first helicopter: t1 = 480 / x - For the second helicopter: t2 = 800 / x

We also know that t1 = t2 - 2. Substituting the values of t1 and t2: 480 / x = (800 / x) - 2

To solve this equation, we can multiply both sides by x to eliminate the denominators: 480 = 800 - 2x

Now, let's solve for x: 2x = 800 - 480 2x = 320 x = 320 / 2 x = 160

So, the speed of both helicopters is 160 km/h.

Now, let's find the time each helicopter was in the air: - For the first helicopter: t1 = 480 / 160 = 3 hours - For the second helicopter: t2 = 800 / 160 = 5 hours

Answer

If the speeds of both helicopters were the same, then the first helicopter was in the air for 3 hours and the second helicopter was in the air for 5 hours.

Please let me know if you need any further assistance.