Question

Жанар к наименьшему двузначному числу несколько раз прибавила наибольшее трехзначное число сумма стала равной наименьшему пятизначному числу сколько раз жанар прибавляла наибольшее трехзначное число?

Answer 1

999*10+10=10000 999+999+999+999+999+999+999+999+999+999=9990 9990+10=10000

Answer 2

Problem Analysis

To solve this problem, we need to find out how many times Zhannar added the largest three-digit number to the smallest two-digit number to obtain a sum equal to the smallest five-digit number.

Solution

Let's denote: - The smallest two-digit number as AB (where A and B are digits). - The largest three-digit number as CDE (where C, D, and E are digits). - The smallest five-digit number as FGHIJ (where F, G, H, I, and J are digits).

We can then form the following equation: AB + CDE * x = FGHIJ where x is the number of times Zhannar added the largest three-digit number to the smallest two-digit number.

Calculation

Let's calculate the values of AB, CDE, and FGHIJ: - The smallest two-digit number is 10. - The largest three-digit number is 999. - The smallest five-digit number is 10000.

Now, we can solve for x: 10 + 999x = 10000

Subtracting 10 from both sides: 999x = 9990

Dividing both sides by 999: x = 10

Answer

Zhannar added the largest three-digit number to the smallest two-digit number 10 times to obtain a sum equal to the smallest five-digit number.