Question

один велосипедист выехал из города в 10 ч утра а второй выехал из города в этом же направлении в 12 ч через какое время второй велосипедист догонит первого если первый двигается со скоростью 9 км ч а второй со скоростью 15 кв ч

Answer 1

15-9=6 км/ч скорость сближения

12-10=2ч прошло, как выехал 1 велосепедист

9*2=18 км было между велосепедистами, когда выехал второй

18/6=3 ч пройдёт как второй велосипедист догонит первого  

 

Answer 2

Problem Analysis

We are given that two cyclists start from the same city in the same direction. The first cyclist starts at 10:00 AM and the second cyclist starts at 12:00 PM. The first cyclist is traveling at a speed of 9 km/h, while the second cyclist is traveling at a speed of 15 km/h. We need to determine how long it will take for the second cyclist to catch up to the first cyclist.

Solution

To solve this problem, we can use the concept of relative speed. The relative speed between the two cyclists is the difference in their speeds. In this case, the relative speed is 15 km/h - 9 km/h = 6 km/h.

We know that the second cyclist starts 2 hours after the first cyclist. During this time, the first cyclist has already covered a distance of 9 km/h * 2 h = 18 km.

Now, the problem reduces to finding the time it takes for the second cyclist to cover a distance of 18 km at a speed of 6 km/h.

Using the formula: time = distance / speed, we can calculate the time it takes for the second cyclist to catch up to the first cyclist.

Let's calculate the time:

Distance = 18 km

Speed = 6 km/h

Time = Distance / Speed = 18 km / 6 km/h = 3 hours

Therefore, the second cyclist will catch up to the first cyclist after 3 hours.

Answer

The second cyclist will catch up to the first cyclist after 3 hours.

Note: The answer is based on the given information and calculations.