Question

Помогите пожалуйста!!!!! Пасажирський поїзд за 4 години пройшов таку саму відстань, як і товарний за 6 год. Знайдить швидкість пасажирського поїзда, якщо відомо, зо вона на 25 км/год більша за швидкість товарного.

Answer 1

Х-скорость товарного
х+25-скорость пассажирского
6х=4(х+25)
6х=4х+100
6х-4х=100
2х=100
х=100:2
х=5о товарный
50+25=75 пасажирский

Answer 2

Пусть длина провода х, тогда (х - 7) - осталось после того, как отрезали 7м.Осталось (по условию задачи) на 4м меньше, чем отрезали, это 7 - 4 = 3мСоставляем уравнение:х - 7 = 3х = 10(м)Длина провода была 10м

Answer 3

Calculating the Speed of the Passenger Train

To find the speed of the passenger train, we can use the formula: Speed = Distance / Time

Given that the passenger train covers the same distance in 4 hours and the freight train covers the same distance in 6 hours, we can use this information to calculate the speed of the passenger train.

Let's denote the distance covered by both trains as "D" and the speed of the passenger train as "S". We also know that the speed of the passenger train is 25 km/h greater than the speed of the freight train.

Using the formula, we can set up the following equations:

1. For the passenger train: S = D / 4 2. For the freight train: (S - 25) = D / 6

We can solve these equations to find the speed of the passenger train.

Solving for the Speed of the Passenger Train

First, we can express the distance in terms of the speed using the formula: Distance = Speed × Time.

For the passenger train: D = S × 4

For the freight train: D = (S - 25) × 6

Now, we can equate the two expressions for distance: S × 4 = (S - 25) × 6

Solving for S: 4S = 6S - 150 2S = 150 S = 75

Conclusion

The speed of the passenger train is 75 km/h.