Question

Из пункта а в пункт в в одном и том же направлении выехали одновременно две машины:из пункта а -легковая , а из пункта в -грузовая. скорость грузовой машины 45 км/ч. какова скорость легковой машины, если она догнала грузовую через 4 ч после выезда, а расстояние между пунктами а и в 156 км?

Answer 1

1)45*4=180(км)-проехал грузовик.
2)180+156=через 336(км) легковушка догнала грузовика
3)пока что вот так это правильно точно

Answer 2

Problem Analysis

We are given that two cars, a passenger car and a truck, start simultaneously from point A and travel in the same direction towards point B. The truck's speed is given as 45 km/h. We need to find the speed of the passenger car if it overtakes the truck after 4 hours of travel, and the distance between points A and B is 156 km.

Solution

Let's assume the speed of the passenger car is x km/h.

We know that the time taken by both vehicles is the same, and the distance traveled by both vehicles is the same. We can use the formula:

Distance = Speed × Time

For the truck: Distance = 45 km/h × 4 h = 180 km

For the passenger car: Distance = x km/h × 4 h

Since the distance traveled by both vehicles is the same, we can equate the two distances:

x km/h × 4 h = 180 km

Simplifying the equation, we can solve for x:

4x = 180

x = 180 / 4

x = 45

Therefore, the speed of the passenger car is 45 km/h.

Answer

The speed of the passenger car is 45 km/h.