Question

Было 6 бидонов цветочного мёда и 10 бидонов липового.В каждом бидоне 48 кг мёда. Сформулируй требование так чтобы её решением было 48*(6+10) ПОМОГИТЕ Я ПОНЯЛА ВСЕ НО КАК ПИСАТЬ КРАТКУЮ ЗАПИСЬ ? 6 бидонов-48 кг И 10 бидонов -48 кг???

Answer 1

48*6=288
48*10=480
6 бидонов}
48кг
10 бидонов}

Answer 2

Problem Formulation

To write a concise representation of the given information, we can use the following equation:

Total amount of honey in 6 cans of flower honey plus 10 cans of linden honey equals 48 times the sum of 6 and 10.

Let's break down the problem and solve it step by step.

Solution

Step 1: Calculate the total amount of honey in 6 cans of flower honey. - Each can contains 48 kg of honey. - Therefore, the total amount of honey in 6 cans of flower honey is 6 multiplied by 48 kg.

Step 2: Calculate the total amount of honey in 10 cans of linden honey. - Each can contains 48 kg of honey. - Therefore, the total amount of honey in 10 cans of linden honey is 10 multiplied by 48 kg.

Step 3: Calculate the sum of the total amounts of honey in the flower honey and linden honey cans. - Add the total amount of honey in 6 cans of flower honey to the total amount of honey in 10 cans of linden honey.

Step 4: Multiply the sum from step 3 by 48. - The result should be equal to 48 times the sum of 6 and 10.

Let's calculate the solution:

Step 1: Total amount of honey in 6 cans of flower honey = 6 * 48 kg = 288 kg.

Step 2: Total amount of honey in 10 cans of linden honey = 10 * 48 kg = 480 kg.

Step 3: Sum of the total amounts of honey = 288 kg + 480 kg = 768 kg.

Step 4: 48 times the sum of 6 and 10 = 48 * (6 + 10) = 48 * 16 = 768 kg.

Therefore, the solution to the given requirement is 768 kg.

I hope this helps! Let me know if you have any further questions.