Question

С трёх лугов собрали 18700кг сена.С первого и второго лугов собрали сена поровну,а с третьего на 700кг больше,чем со второго.Сколько центнеров сена собрали с каждого луга?

Answer 1

Х+х+х+700=18700
3х=18700-700
3х=18000
3х=18000:3
х=6000
1луг 6000кг
2 луг 6000кг
3 луг кг6700кг

Answer 2

Решим задачу уравнением:
3x + 700 = 18700
3x = 18700 - 700 = 18000
x = 18000/3 = 6000
Т.е. с первого и второго лугов собрали по 6000 кг. сена (60 центнеров), а с третьего на 700 кг. больше (67 центнеров).

Answer 3

Problem Analysis

We are given that a total of 18,700 kg of hay was collected from three meadows. The hay was collected in such a way that the first and second meadows produced an equal amount, while the third meadow produced 700 kg more than the second meadow. We need to determine how many hundredweights (центнеров) of hay were collected from each meadow.

Solution

Let's assume that the amount of hay collected from each meadow is represented by variables: x for the first meadow, y for the second meadow, and z for the third meadow.

From the given information, we can form the following equations: 1. The sum of hay collected from all three meadows is 18,700 kg: x + y + z = 18,700. 2. The hay collected from the first and second meadows is equal: x = y. 3. The hay collected from the third meadow is 700 kg more than the second meadow: z = y + 700.

To solve this system of equations, we can substitute the value of y from equation 2 into equations 1 and 3.

Substituting x = y into equation 1: y + y + z = 18,700, 2y + z = 18,700.

Substituting x = y into equation 3: z = y + 700.

Now we have a system of two equations with two variables: 2y + z = 18,700, z = y + 700.

We can solve this system of equations to find the values of y and z.