Question

Периметр прямоугольника равен 60 см . ширина прямоугольника на 4 см меньше длины .чему равны длина и ширина прямоугольника?

Answer 1

Ширина=х. длина=х+4. получаем уравнение: х+х+х+4+х+4=60. то есть 4х+8=60. 4х=60-8=52. х=52:4=13. 13 см-ширина. длина=13+4=17 см

Answer 2

Р=(a+b)•2
Полупериметр a+b или Р:2
Полупериметр=60:2=30см
Пусть a=x, тогда b=х+4
х+(х+4)=30
х+х+4=30
2х=26
х=13 см ширина
Длина = х+4=13+4=17см

Answer 3

Problem Analysis

We are given that the perimeter of a rectangle is 60 cm, and the width of the rectangle is 4 cm less than the length. We need to find the length and width of the rectangle.

Solution

Let's assume the length of the rectangle is L cm. According to the problem, the width of the rectangle is 4 cm less than the length, so the width is L - 4 cm.

The perimeter of a rectangle is given by the formula: P = 2(L + W), where P is the perimeter, L is the length, and W is the width.

Substituting the values into the formula, we get: 60 = 2(L + (L - 4)).

Simplifying the equation, we have: 60 = 2(2L - 4).

Expanding the equation, we get: 60 = 4L - 8.

Adding 8 to both sides of the equation, we have: 68 = 4L.

Dividing both sides of the equation by 4, we get: L = 17.

Therefore, the length of the rectangle is 17 cm.

Substituting the value of L into the equation for the width, we have: W = L - 4 = 17 - 4 = 13.

Therefore, the width of the rectangle is 13 cm.

Answer

The length of the rectangle is 17 cm and the width of the rectangle is 13 cm.