Question

В одному ящику було в 7 разів більше апельсинів ніж у другому Коли з першого ящика взяли 38 апельсинів,а здругого14 то в другому залишилося на 78 апелсинів менше ніж у першому.Скільки було в кожному ящику спочатку?

Answer 1

В первом ящике - 7х
во втором ящике - х
с первого ящика взяли 38 , получаем 7х-38
со второго 14, получаем х-14. в результате во втором меньше , чем в первом на 78. уравниваем и получаем уравнение
7х-38=х-14+78
7х-38=х+64
7х-х=64+38
6х=102
х=102:6
х=17 (апельсинов) - во втором ящике было сначала
17×7=119 (ап) - в первом ящике было сначала

Answer 2

To solve this problem, let's assign variables to represent the number of oranges in each box. Let's call the number of oranges in the first box "x" and the number of oranges in the second box "y".

According to the problem, the first box had 7 times more oranges than the second box. So we can write the equation: x = 7y.

We also know that when 38 oranges were taken from the first box and 14 oranges were taken from the second box, the second box had 78 fewer oranges than the first box. This can be represented by the equation: y - 14 = x - 38 - 78.

Now we can solve these equations simultaneously to find the values of x and y.

Solving the equations:

From the first equation, we can substitute the value of x in terms of y into the second equation:

7y - 14 = 7y - 38 - 78.

Simplifying the equation:

7y - 14 = 7y - 116.

Subtracting 7y from both sides:

-14 = -116.

This equation is not possible to solve because it leads to a contradiction. It means that there is no solution that satisfies the given conditions.

Therefore, there is no solution to this problem.