Question

Ре­ши­те урав­не­ние .

Answer 1

$(\cos^2x-\cos x)\sqrt{-11tgx}=0;\\ tgx\geq0;\\ D(f):\ \ \ -\frac\pi2 +\pi n<x\leq\pi n;\\D(f):\ x\in\left(-\frac\pi2+\pi n;\pi n\right]\ n\in Z;\\\cos^2x-\cos x=0;\\\cos x=0\ \ x=\frac\pi2+\pi n\notin D(f);\\\cos x=1\ \ x=2\pi n\in D(f);\\tgx=0;\ \ x=\pi n;\\\\\\\\\\<span>x=\pi n,\ n\in Z.$