Question

На первой пасеке с каждого улья получили по 60 килограмм меда а на второй по 70 кг. всего собрали на двух пасеках 4510 кг. сколько ульев было на каждой пасеки если на второй пасеки на 5 ульев больше.

Answer 1

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Answer 2

Problem Analysis

We are given that on the first apiary (пасека) each hive (улей) produced 60 kg of honey, while on the second apiary each hive produced 70 kg of honey. The total amount of honey collected from both apiaries is 4510 kg. We need to determine the number of hives on each apiary, given that there are 5 more hives on the second apiary than on the first apiary.

Solution

Let's assume that there are 'x' hives on the first apiary. Since there are 5 more hives on the second apiary, the number of hives on the second apiary would be 'x + 5'.

The total amount of honey collected from the first apiary would be the product of the number of hives and the amount of honey produced by each hive: 'x * 60 kg'.

Similarly, the total amount of honey collected from the second apiary would be: '(x + 5) * 70 kg'.

According to the problem, the total amount of honey collected from both apiaries is 4510 kg. Therefore, we can set up the following equation:

'x * 60 kg + (x + 5) * 70 kg = 4510 kg'

Now, let's solve this equation to find the value of 'x'.

Calculation

Expanding the equation:

'60x + 70(x + 5) = 4510'

Simplifying:

'60x + 70x + 350 = 4510'

Combining like terms:

'130x + 350 = 4510'

Subtracting 350 from both sides:

'130x = 4160'

Dividing both sides by 130:

'x = 32'

Therefore, there are 32 hives on the first apiary. Since there are 5 more hives on the second apiary, there would be '32 + 5 = 37' hives on the second apiary.

Answer

There are 32 hives on the first apiary and 37 hives on the second apiary.