Question

Фрезеровщики бригады затратили на обработку одной детали разное время в мин,представленное в виде ряда данных:40;37;35;36;32;42;32;38;32.На сколько медиана этого набора отличается от среднего арифметического?

Answer 1

Медиана=36
ср.арифм.36
следовательно их разница=0

Answer 2

Calculation of Median and Mean

To find the median and mean of the given set of data, we first need to arrange the data in ascending order:

32, 32, 32, 35, 36, 37, 38, 40, 42

The median is the middle value of the data set when arranged in ascending order. Since we have 9 data points, the median will be the 5th value, which is 36.

The mean, or arithmetic average, is calculated by summing up all the values and dividing by the total number of values. In this case, the sum of the data is 326, and there are 9 values. Therefore, the mean is 326/9 = 36.22 (rounded to two decimal places).

Difference between Median and Mean

To find the difference between the median and the mean, we subtract the mean from the median:

36 - 36.22 = -0.22

Therefore, the difference between the median and the mean of the given data set is approximately -0.22.

Please note that the difference is negative, indicating that the mean is slightly higher than the median.