
В мастерской сшили 120 спальных мешков за 6 дней, изготавливая одинаковое количество мешков каждый
день. За сколько дней сошьют 100 спальных мешков, если ежедневно будут шить на 5 мешков больше?

Ответы на вопрос

Краткая запись:
6 дней-120 спальных мешков
1 день-? мешков? дней-100 спальных мешков,если на 5м.б.
Решение: 120:6=20-мешков один день
20+5=25(мешков)
100:25=4(дня)



25- в день
100:25=4



Problem Analysis
In a workshop, 120 sleeping bags were sewn in 6 days, with the same number of bags being sewn each day. The task is to determine how many days it will take to sew 100 sleeping bags if 5 more bags are sewn each day.Solution
To solve this problem, we can use the concept of proportions. Let's assume that the number of bags sewn each day is represented by x.According to the given information, 120 sleeping bags were sewn in 6 days, with the same number of bags being sewn each day. This can be represented as:
120 bags / 6 days = x bags / 1 day
To find the value of x, we can cross-multiply and solve for x:
120 bags * 1 day = 6 days * x bags
Simplifying the equation:
120 = 6x
Dividing both sides of the equation by 6:
20 = x
So, each day, 20 sleeping bags were sewn.
Now, we need to determine how many days it will take to sew 100 sleeping bags if 5 more bags are sewn each day. Let's represent the number of days required as y.
According to the new scenario, the number of bags sewn each day is 20 + 5 = 25.
We can set up the following proportion:
120 bags / 6 days = 100 bags / y days
Cross-multiplying and solving for y:
120 bags * y days = 6 days * 100 bags
Simplifying the equation:
120y = 600
Dividing both sides of the equation by 120:
y = 600 / 120
Simplifying further:
y = 5
Therefore, it will take 5 days to sew 100 sleeping bags if 5 more bags are sewn each day.
Answer
It will take 5 days to sew 100 sleeping bags if 5 more bags are sewn each day.

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