Question

3xy+4xz=x(3y=4z)= pq+2mp= 6ay-3az=9a^2= (x^2)^3= (8x)^5:(4x)^5= 7^11:7^9= (3a)^5= 7^4y= (64)^3= (10n)^6:(5n)^6= x^2+xy+y^2= (2n+3)^2= (x-y)^2= p^2+4pq+q^2=

Answer 1

Здравствуйте в этом случае я буду делать в этом случае мы постараемся проверить эти сведения и внести изменения цен на жилье в Москве и России и Украины и мира по футболу в этом году в Москве и по ссылке вы сможете узнать про то что надо сделать так чтобы не забыть про то как то так. но я не знаю, что являетесь, что 5

Answer 2

To solve the given expressions, let's take them one by one:

1. 3xy + 4xz = x(3y + 4z) This expression can be simplified by factoring out the common term 'x', giving us: 3xy + 4xz = x(3y + 4z)

2. pq + 2mp = 6ay - 3az Here, we can rearrange the terms and factor out the common term 'p', giving us: pq + 2mp = p(q + 2m) = 6ay - 3az

3. 9a^2 = (x^2)^3 This expression involves the exponentiation of 'x' and 'a'. To simplify it, we can rewrite it as: 9a^2 = x^6

4. (8x)^5 / (4x)^5 This expression involves division of two terms with the same base but different exponents. We can simplify it by subtracting the exponents, giving us: (8x)^5 / (4x)^5 = 2^5 = 32

5. 7^11 / 7^9 Here, we have division of two terms with the same base. By subtracting the exponents, we get: 7^11 / 7^9 = 7^2 = 49

6. (3a)^5 This expression involves raising '3a' to the power of 5. We can simplify it by multiplying the exponents, giving us: (3a)^5 = 3^5 * a^5 = 243a^5

7. 7^4y This expression involves raising 7 to the power of '4y'. It cannot be further simplified without knowing the value of 'y'.

8. (64)^3 Here, we have the cube of 64. Evaluating it, we get: (64)^3 = 262,144

9. (10n)^6 / (5n)^6 This expression involves division of two terms with the same base but different exponents. By subtracting the exponents, we get: (10n)^6 / (5n)^6 = 2^6 = 64

10. x^2 + xy + y^2 This expression cannot be further simplified without knowing the values of 'x' and 'y'.

11. (2n + 3)^2 Here, we have the square of the binomial '2n + 3'. Expanding it, we get: (2n + 3)^2 = 4n^2 + 12n + 9

12. (x - y)^2 This expression involves squaring the binomial 'x - y'. Expanding it, we get: (x - y)^2 = x^2 - 2xy + y^2

13. p^2 + 4pq + q^2 This expression involves the sum of three terms. It cannot be further simplified without knowing the values of 'p' and 'q'.

I hope this helps! Let me know if you have any further questions.