Question

Из пункта А в пункт Б, расстояние между которыми 500км, выехал автобус со скоростью 58км/ч. Через 4 часа из пункта Б навстречуему выехал легковой автомобиль и ещё через 2 часа встретились с автобусом. найдите скорость легкового автомобиля

Answer 1

58х6=348км путь пройденный до встречи с автомобилем
(500-348):2=76км/ч скорость автомобиля

Answer 2

58*6=348 км путь пройденный до встречи с автомобилем
(500*348):2 76 км/ч скорость автомобиля

Answer 3

Problem Analysis

We are given the following information: - The distance between point A and point B is 500 km. - A bus starts from point A and travels at a speed of 58 km/h. - After 4 hours, a car starts from point B and travels towards the bus. - After 2 more hours, the car and the bus meet.

We need to find the speed of the car.

Solution

Let's calculate the distance covered by the bus in 4 hours: Distance covered by the bus = Speed of the bus * Time = 58 km/h * 4 h = 232 km.

After 4 hours, the bus has covered 232 km. The remaining distance between the bus and point B is 500 km - 232 km = 268 km.

Now, let's calculate the time it takes for the car to cover the remaining distance of 268 km: Time = Distance / Speed = 268 km / Speed.

We know that the car and the bus meet after 2 more hours, so the total time taken by the car is 2 hours.

Setting up an equation: 2 hours = 268 km / Speed.

Solving for Speed: Speed = 268 km / 2 hours = 134 km/h.

Therefore, the speed of the car is 134 km/h.

Answer

The speed of the car is 134 km/h.