Question

Петя вдвое старше, чем оля. У оли было в 3 раза больше орехов чем у пети. кол-во орехов у Оли больше количества лет Пети на 35. А кол-во орехов у пети больше кол-ва лет Оли в 3 раза. Сколько лет каждому

Answer 1

Х- кол- во лет Оле
2х- кол- во лет Пете

у- кол-во орехов у Пети
3у- кол- во орехов у Оли
 Составляем систему уравнений.
3у=2х+35
у=3х

3*3х=2х+35
9х-2х=35
7х=35
х=35:7
х=5 -лет Оле
х*2=10 -лет Пете

Answer 2

Problem Analysis

We are given the following information: - Petya is twice as old as Olya. - Olya has three times as many nuts as Petya. - The number of nuts Olya has is greater than Petya's age by 35. - The number of nuts Petya has is three times greater than Olya's age.

We need to find the ages of both Petya and Olya.

Solution

Let's assume Petya's age is x years and Olya's age is y years.

From the given information, we can write the following equations: 1. Petya is twice as old as Olya: x = 2y. 2. Olya has three times as many nuts as Petya: y = 3x. 3. The number of nuts Olya has is greater than Petya's age by 35: y = x + 35. 4. The number of nuts Petya has is three times greater than Olya's age: x = 3y.

We can solve these equations to find the values of x and y.

Substituting equation 1 into equation 4, we get: 2y = 3y.

Simplifying, we find: y = 0.

Substituting this value of y into equation 3, we get: 0 = x + 35.

Simplifying, we find: x = -35.

However, it is not possible for someone to have a negative age. Therefore, there is no solution to this problem.

Conclusion

Based on the given information, there is no possible solution for the ages of Petya and Olya that satisfies all the conditions.