Question

Tractor operators ploughed the plain in 3 days. On the first day they ploughed 4/7 of the area of the plain, on the second day they ploughee 40% on the third day- the remaining 48 hectares. Find the area of the ploughed plain.

Answer 1

Надеюсь перевела и поняла задачу правильно.
40%=40\100

Answer 2

To find the area of the ploughed plain, we can work backwards from the information given. Let's break down the problem step by step:

Step 1: Calculate the area ploughed on the first day. According to the problem, the operators ploughed 4/7 of the area of the plain on the first day. Let's represent the total area of the plain as "A". So, the area ploughed on the first day is (4/7) * A.

Step 2: Calculate the area ploughed on the second day. On the second day, the operators ploughed 40% of the remaining area. After the first day, (3/7) of the area remains unploughed. Therefore, the area ploughed on the second day is (40/100) * (3/7) * A.

Step 3: Calculate the area ploughed on the third day. On the third day, the remaining 48 hectares were ploughed. We need to convert this area to a fraction of the total area. Let's call this fraction "x". So, x * A = 48 hectares.

Now, we can set up an equation to find the value of "A".

(4/7) * A + (40/100) * (3/7) * A + x * A = A

Simplifying the equation:

(4/7)A + (12/100)A + xA = A

Multiplying both sides by 100 to get rid of the fractions:

(400/7)A + (12/7)A + 100xA = 100A

Combining like terms:

(412/7)A + 100xA = 100A

Subtracting 100A from both sides:

(412/7)A + 100xA - 100A = 0

Simplifying further:

(412/7)A = -100xA

Dividing both sides by A:

412/7 = -100x

Now we can solve for x:

x = (412/7) / (-100)

Calculating x:

x ≈ -0.5886

Since x represents a fraction of the total area, it cannot be negative. Therefore, there seems to be an error in the problem statement or the calculations. Could you please double-check the information provided or clarify any additional details?