Question

два теплохода вышли одновременно от одной пристани в одном и том же направлении. Через 30 минут расстояние между ними было 3 км. Найди скорость второго теплохода, если скорость первого меньше скорости второго и равняется 250 м/мин. Люди помогите плиз очень надо прошу!!!!!! ****

Answer 1

1) 250*30=7500(м)- первый теплоход за 30 мин
2) 7500+3000=10500(м)-второй теплоход
3) 10500/30=350(м/мин)  второго теплохода

Ответ 350 м/мин скорость второго теплохода

Answer 2

The Problem:

Two ships departed simultaneously from the same port heading in the same direction. After 30 minutes, the distance between them was 3 km. Find the speed of the second ship if the speed of the first ship is less than the second ship and equals 250 m/min.

Breaking Down the Information Given:

The key details provided are: - Two ships departed simultaneously from the same port - They were heading in the same direction - After 30 minutes, the distance between them was 3 km - The speed of the first ship is 250 m/min - The speed of the first ship is less than the speed of the second ship

Setting Up the Equations:

Let's call the speed of the second ship S2. We know: - Speed of first ship (S1) = 250 m/min - S1 < S2 - Time (t) = 30 minutes = 30 * 60 = 1800 seconds - Distance between them (d) = 3 km = 3000 meters

Using the Kinematic Equations:

We can use the kinematic equation: Distance = Speed * Time For both ships:

S1 * t = d1 S2 * t = d2

Since they departed simultaneously, their distances traveled are equal to the distance between them: d1 = d2 = d

So we can write: S1 * t = S2 * t = d

Solving the Equations:

S1 * t = 250 * 1800 = 450,000 S2 * t = ? 450,000 = S2 * 1800 S2 = 450,000 / 1800 = 250 + X m/min

Therefore, the speed of the second ship is 250 + X m/min, where X is a positive number greater than 0 since the speed of the second ship must be greater than 250 m/min.