Question

Периметр равнобедренного треугольника равен 324, а основание-160.Найдите площадь треугольника.

Answer 1

P=(324-160)=164 
ответ:164 площадь треугольника 
     НАВЕРНО ТАК;)

Answer 2

324-160=164
164:2=82
82*164=13448

Answer 3

Answer in detail. The perimeter of an isosceles triangle is 324, and the base is 160. Find the area of the triangle.

To find the area of the triangle, we need to know the height of the triangle. We can use the Pythagorean theorem to find the height, since the triangle is isosceles and has two equal sides. Let h be the height and x be the length of each equal side. Then we have:

$$h^2 + \left(\frac{160}{2}\right)^2 = x^2$$

We also have the equation for the perimeter:

$$160 + 2x = 324$$

Solving for x, we get:

$$x = \frac{324 - 160}{2} = 82$$

Substituting x into the first equation, we get:

$$h^2 + 80^2 = 82^2$$

Solving for h, we get:

$$h = \sqrt{82^2 - 80^2} = 12$$

Now we can find the area of the triangle using the formula:

$$A = \frac{1}{2}bh$$

where b is the base and h is the height. Substituting the values, we get:

$$A = \frac{1}{2}(160)(12) = 960$$

Therefore, the area of the triangle is 960 square units.