Question

*Перед началом игры капитаны бросают жребий, чтобы определить какая из команд выиграет право первой подачи. Команда "Львы" по очереди играет с командами "Тигры" и "Орлы". Найдите вероятность того. что право первой подачи в обоих играх получит команда "Львы".

Answer 1

Вероятность равна 1/4, т.к. возможны 4 случая и только в одном из них обе подачи будут за" Львами"

Answer 2

Probability of the "Lions" winning the right to serve first in both games

To find the probability of the "Lions" winning the right to serve first in both games, we need to determine the probability of the "Lions" winning the coin toss in each game and then multiply those probabilities together.

Let's assume that the coin toss is fair and has an equal chance of landing on heads or tails. Therefore, the probability of the "Lions" winning the coin toss in each game is 0.5 or 50%.

To find the probability of both events happening, we multiply the probabilities together. Since the events are independent, the probability of both events occurring is the product of their individual probabilities.

Therefore, the probability of the "Lions" winning the right to serve first in both games is:

0.5 * 0.5 = 0.25 or 25%.

Please note that this calculation assumes that the coin toss is fair and that there are no other factors that could influence the outcome of the coin toss.