Question

Поезд отправился из Санкт-Петербурга в 23 ч 15 мин и прибыл в москву в 6 ч 25 мин следующего дня.По пути он сделал 2 остановки: на станции Бологое и в городе Тверь,по 5 мин каждая.С какой средней скоростью двигался этот поезд,если он прошёл 651 км с поеснением

Answer 1

24ч 0мин - 23 ч 15 мин=45мин
6ч 25мин + 45мин=7ч 10мин
7ч 10мин - 10мин=7ч
651/7=93км/ч
Пояснения сам

Answer 2

Calculation of Average Speed

To calculate the average speed of the train, we need to determine the total time it took for the train to travel from St. Petersburg to Moscow and the total distance covered.

Given information: - Departure time from St. Petersburg: 23:15 - Arrival time in Moscow: 6:25 the next day - Number of stops: 2 (Bologoye station and Tver city), each lasting 5 minutes - Distance traveled: 651 km

To calculate the total time, we need to consider the time spent on the stops. Let's break down the journey into different segments:

1. Segment 1: St. Petersburg to Bologoye station - Distance: Unknown - Time taken: Unknown

2. Segment 2: Bologoye station to Tver city - Distance: Unknown - Time taken: Unknown

3. Segment 3: Tver city to Moscow - Distance: Unknown - Time taken: Unknown

To calculate the time taken for each segment, we need to subtract the time spent on the stops from the total travel time.

Let's calculate the time taken for each segment:

1. Time taken for Segment 1: - Departure time from St. Petersburg: 23:15 - Arrival time at Bologoye station