Question

В 11 часов с аэродрома вылетели одновременно противоположных направлениях два самолёта.В 14 часов расстояние между ними было 3540 км. Один из них летел со скоростью 620 км в час. С какой скоростью летел другой самолёт? ПОМОГИТЕ!

Answer 1

14-11=3 часа самолеты были в полете                                                                    3540:3=1180 км/час скорость удаления самолетов                                                 1180-620=560 км/час скорость 2 самолета

Answer 2

14-11=3 часа в пути
620*3= 1860 - пролетел один
3540-1860=1680 - пролетел другой
1680\3=560 км/ч - летел другой

Answer 3

Problem Analysis

We have two planes that took off simultaneously from an airport in opposite directions. At 14:00, the distance between them was 3540 km. We know that one of the planes was flying at a speed of 620 km/h. We need to find the speed of the other plane.

Solution

Let's assume that the speed of the second plane is x km/h.

We can use the formula: distance = speed × time.

From 11:00 to 14:00, three hours have passed. So, the first plane has traveled a distance of 620 × 3 = 1860 km.

Let's represent the distance traveled by the second plane as d km.

The total distance between the two planes is the sum of the distances traveled by each plane: 1860 km + d km = 3540 km.

To find the speed of the second plane, we can rearrange the equation: d km = 3540 km - 1860 km.

Simplifying the equation, we get: d km = 1680 km.

Therefore, the speed of the second plane is 1680 km/h.

Answer

The second plane was flying at a speed of 1680 km/h.