Question

через 5 мин после вылета спортивного самолёта в том же направлении вылетел второй самолёт и спустя 15 мин догнал первый.Скорость первого самолёта составляла 6 км мин.Какова скорость второга. ПОМОГИТЕ РЕШИТЬ ПО ДЕЙСТВИЯМ!

Answer 1

1) 5+15=20 (мин) потребовалось времени 1-му самолету

2) 20*6=120 (км) пройденное расстояние

3) 15-5=10 (мин) - потребовалось второму самолету на преодоление этого расстояния

4) 120/10= 12 (км/мин) - скорость второго самолета

Answer 2

5+15=20мин время в пути первого самолета

20*6=120км путь первого самолета

120:15=8км/мин скорость второго самолета

Answer 3

Problem Analysis

We are given that a second plane takes off in the same direction as the first plane, 5 minutes after the first plane. The second plane catches up to the first plane 15 minutes later. We need to find the speed of the second plane.

Solution

Let's assume the speed of the second plane is x km/min.

The first plane has a speed of 6 km/min and a head start of 5 minutes. So, the distance covered by the first plane when the second plane takes off is: distance_1 = 6 km/min * 5 min = 30 km.

When the second plane catches up to the first plane, the total time elapsed is 15 minutes. During this time, the first plane has been flying for 20 minutes (5 minutes before the second plane took off and 15 minutes after). The second plane has been flying for 15 minutes.

Since both planes cover the same distance when the second plane catches up to the first plane, we can set up the equation: distance_1 = distance_2.

Substituting the values we know: 30 km = 15 min * x km/min.

Simplifying the equation, we can solve for x: x = 30 km / 15 min = 2 km/min.

Therefore, the speed of the second plane is 2 km/min.

Answer

The speed of the second plane is 2 km/min.