Question

Мастер за 8 часов обрабатывает 320 деталей,а ученик за 6ч 192 детали.Вдвоём они должны были обработать 332 детали.Первые 4 часа мастер мастер работал один,потом они работали вместе . Оставшуюся часть заказа выполнил ученик за 2 ч. В течение какого времени мастер и ученик работали одновременно?

Answer 1

320:8=40 деталей за 1 час(скорость мастера)
192:6=32 детали за 1 час(скорость ученика)

32*2=64
332-64=268
4*40=160
268-160=108 деталей(делали вместе мастер и ученик)
вместе они работали 1.5 часа

Answer 2

Problem Analysis

We are given that a master can process 320 parts in 8 hours, and an apprentice can process 192 parts in 6 hours. Together, they were supposed to process 332 parts. The master worked alone for the first 4 hours, and then they worked together. The remaining part of the order was completed by the apprentice in 2 hours. We need to determine the amount of time the master and apprentice worked together.

Solution

Let's break down the problem step by step:

1. The master can process 320 parts in 8 hours, so their rate of work is 40 parts per hour. 2. The apprentice can process 192 parts in 6 hours, so their rate of work is 32 parts per hour. 3. Together, their combined rate of work is 40 + 32 = 72 parts per hour. 4. The master worked alone for the first 4 hours, so they processed 40 parts per hour x 4 hours = 160 parts. 5. The remaining part of the order that needed to be processed is 332 - 160 = 172 parts. 6. The apprentice completed the remaining part of the order in 2 hours, so their rate of work is 172 parts / 2 hours = 86 parts per hour. 7. To find the amount of time the master and apprentice worked together, we can use the formula: total work / combined rate of work. - Total work = 172 parts - Combined rate of work = 72 parts per hour - Time worked together = 172 parts / 72 parts per hour = 2.39 hours.

Therefore, the master and apprentice worked together for approximately 2.39 hours.

Answer

The master and apprentice worked together for approximately 2.39 hours.