
Из а в б отправились одновременно 2 человека 1 пешком другой на велосипеде в то же время из б в а
вышел автомобиль который встретился с велосипедистом через 4 часа а а с пешеходом через 5 часов после своего выезда из б найдите расстояние от а до б зная что пешеход проходит по 6 км/ч а велосипедист по 15 км/ ч?

Ответы на вопрос

расстояние 4*(х+15)=5(х+6)
4х+60=5х+30
5х-4х=60-30
х=30км/ч
4*(30+15)=4*45=180км от А до В



Problem Analysis
We have two people, one walking and the other cycling, who start simultaneously from point A to point B. At the same time, a car leaves point B and meets the cyclist after 4 hours and the pedestrian after 5 hours. We need to find the distance between points A and B, given that the pedestrian walks at a speed of 6 km/h and the cyclist rides at a speed of 15 km/h.Solution
Let's assume the distance between points A and B is d kilometers.The time it takes for the car to meet the cyclist is 4 hours, and the cyclist's speed is 15 km/h. Therefore, the distance traveled by the cyclist in 4 hours is 15 km/h * 4 h = 60 km.
Similarly, the time it takes for the car to meet the pedestrian is 5 hours, and the pedestrian's speed is 6 km/h. Therefore, the distance traveled by the pedestrian in 5 hours is 6 km/h * 5 h = 30 km.
Since the car meets the cyclist after 4 hours and the pedestrian after 5 hours, the car must have traveled the same distance in both cases. Therefore, the distance traveled by the car is equal to the sum of the distances traveled by the cyclist and the pedestrian.
So, we have the equation: 60 km + 30 km = d km.
To find the value of d, we can simply add the distances traveled by the cyclist and the pedestrian.
Calculation
The distance between points A and B is d km.The distance traveled by the cyclist in 4 hours is 60 km.
The distance traveled by the pedestrian in 5 hours is 30 km.
Therefore, the distance between points A and B is 60 km + 30 km = 90 km.
Answer
The distance between points A and B is 90 km.Note: The sources provided did not contain relevant information for this specific problem.


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