Question

Сплюшкин пробыл под водой в луже вчетверо больше, чем ленивчик , а ленивчик на 9 секунд меньше, чем сплюшкин . Сколько секунд под водой пробыл хрюшкин , если известно , что он про держался на 1 секунду дольше сплюшкина??

Answer 1

Из задачи означает , что сплюшкин пробыл под водой 36 секунд , так как он пробыл в четверо раза дольше  ленивчика , на ленивчик на  9 секунд меньше сплюшкина , значит хрюшкин под водой пробыл 35 секунд . 

Answer 2

Calculating the Time Spent Underwater

To calculate the time spent underwater by each character, we can use the given information about their relative durations.

Let's denote: - S as the time Sploshy spent underwater - L as the time Lazy spent underwater - H as the time Hoggins spent underwater

We are given the following information: 1. Sploshy spent four times longer underwater than Lazy: S = 4L 2. Lazy spent 9 seconds less than Sploshy: L = S - 9 3. Hoggins spent 1 second longer than Sploshy: H = S + 1

Using these equations, we can solve for the time Hoggins spent underwater.

Solving for Hoggins' Time Underwater

First, we can substitute the value of L from the second equation into the first equation: S = 4(S - 9)

Expanding and solving for S: S = 4S - 36 -3S = -36 S = 12

So, Sploshy spent 12 seconds underwater.

Now, we can find the time Lazy spent underwater using the second equation: L = 12 - 9 L = 3

Lazy spent 3 seconds underwater.

Finally, we can find the time Hoggins spent underwater using the third equation: H = 12 + 1 H = 13

Therefore, Hoggins spent 13 seconds underwater.