Question

Из пункта А вышел пешеход со скоростью 6 км/ч, а через 2 часа за ним следом выехал велосипедист со скоростью 10 км/ч. Через сколько часов велосипедист догонит пешехода?

Answer 1

* - умножить
: - поделить

Ответ:
1) 6*2=12 (км) - прошёл пешеход за 2 часа
2) 10-6=4 (км/ч) - будет уменьшаться расстояние между ними
3) 12:4=3 (ч)
Ответ: через 3 часа

Answer 2

Problem Analysis

We are given that a pedestrian walks at a speed of 6 km/h and a cyclist starts riding 2 hours later at a speed of 10 km/h. We need to determine how many hours it will take for the cyclist to catch up to the pedestrian.

Solution

To solve this problem, we can set up an equation based on the relative speeds of the cyclist and the pedestrian. Let's assume that it takes "t" hours for the cyclist to catch up to the pedestrian.

The distance covered by the pedestrian in "t" hours is given by: Distance_pedestrian = Speed_pedestrian * t

The distance covered by the cyclist in "t" hours is given by: Distance_cyclist = Speed_cyclist * (t - 2)

Since the cyclist catches up to the pedestrian, the distances covered by both of them are equal. Therefore, we can set up the following equation: Distance_pedestrian = Distance_cyclist

Substituting the values, we get: Speed_pedestrian * t = Speed_cyclist * (t - 2)

Now, we can solve this equation to find the value of "t".

Calculation

Let's substitute the given values into the equation and solve for "t":

6 * t = 10 * (t - 2)

Simplifying the equation: 6t = 10t - 20

Bringing the "t" terms to one side: 4t = 20

Dividing both sides by 4: t = 5

Therefore, it will take 5 hours for the cyclist to catch up to the pedestrian.

Answer

The cyclist will catch up to the pedestrian after 5 hours.

Explanation

The pedestrian starts walking at a speed of 6 km/h. After 2 hours, the cyclist starts riding at a speed of 10 km/h. Since the cyclist is faster, it will take some time for them to catch up to the pedestrian. After 5 hours, the cyclist will have covered a greater distance and will catch up to the pedestrian.