Question

Из двух сёл расстояние между которыми равно 20км одновременно вышли навстречу друг другу два пешехода и встретились через 2ч после начала движения. Найдите скорость каждого пешехода если известно что первый пешеход проходит за 4ч на 12км больше чем второй за 3ч.

Answer 1

V1-x
V2-y
{(x+y)2=20
{4x-3y=12
{2x+2y=20|*3
{4x-3y=12|*2
+{6x+6y=60
+{8x-6y=24
14x=84|:14
x=6
(6+y)2=20
12+2y=20
2y=20-12
2y=8|:2
y=4

Answer 2

Problem Analysis

We are given that two pedestrians start walking towards each other from two villages that are 20 km apart. They meet each other 2 hours after the start of their journey. We are also given that the first pedestrian covers a distance that is 12 km more than the second pedestrian in 4 hours, while the second pedestrian covers the distance in 3 hours.

Solution

Let's assume the speed of the first pedestrian is x km/h and the speed of the second pedestrian is y km/h.

We can use the formula speed = distance / time to find the speeds of the pedestrians.

From the given information, we can write the following equations:

1. The first pedestrian covers a distance of 20 km in 4 hours, so x = 20 / 4 = 5 km/h. 2. The second pedestrian covers a distance of 20 km in 3 hours, so y = 20 / 3 ≈ 6.67 km/h.

Therefore, the speed of the first pedestrian is 5 km/h and the speed of the second pedestrian is 6.67 km/h.

Answer

The speed of the first pedestrian is 5 km/h and the speed of the second pedestrian is 6.67 km/h.