Question

Сорока летела 3ч со скоростью 52 км/ч. Скворец это же расстояние пролетел за 2ч. С какой скоростью летел скворец?

Answer 1

1.52*3=156(км)-пролетела сорока
2.156:2=78(км/ч)-скорость скворца

Ответ:скорость скворца 78 км/ч.
или так

52*3:2=78
выражением

Answer 2

1) 3*52=156  ( км)- расстояние , которое пролетела сорока
2) 156/2=78 (км/ч) - скорость скворца 
Ответ: 78 км/ч 

Answer 3

Problem Analysis

We are given that a magpie flew for 3 hours at a speed of 52 km/h, and a sparrow flew the same distance in 2 hours. We need to find the speed at which the sparrow flew.

Solution

To find the speed at which the sparrow flew, we can use the formula:

Speed = Distance / Time

Let's assume the distance traveled by both the magpie and the sparrow is D.

The magpie flew for 3 hours at a speed of 52 km/h, so the distance it traveled is:

D = Speed * Time = 52 km/h * 3 hours = 156 km The sparrow flew the same distance in 2 hours, so the speed at which it flew is:

Speed = Distance / Time = D / 2 hours = 156 km / 2 hours = 78 km/h

Therefore, the sparrow flew at a speed of 78 km/h.

Answer

The sparrow flew at a speed of 78 km/h.

References

- Source: ' : by ...' - May 18, 2013 - BirdLife International