Question

В сервисе отремонрировали 40 моторов автомобилей и мотоциклов. Сколько отремонтировано автомобилей и сколько мотоциклов, исли из сервиса выкатилось 100 колёс? Решите задачу уравнением Очень нодо!!!

Answer 1

Вот решение задачи уравнением

Answer 2

Х-40=100 х=100-40 х=60 60+40=100

Answer 3

Problem Analysis

To solve this problem, we can use a system of equations. Let's denote the number of repaired cars as C and the number of repaired motorcycles as M. We are given that a total of 40 motors were repaired, so we have the equation C + M = 40. Additionally, we know that 1 car has 4 wheels and 1 motorcycle has 2 wheels, and a total of 100 wheels were rolled out of the service. This gives us the equation 4C + 2M = 100.

Solving the System of Equations

We can solve the system of equations using substitution or elimination. Let's use the substitution method to solve for C and M.

First, we can solve the equation C + M = 40 for C: C = 40 - M

Next, we substitute this value of C into the second equation: 4(40 - M) + 2M = 100 160 - 4M + 2M = 100 160 - 2M = 100 -2M = -60 M = 30

Now that we have the value of M, we can substitute it back into the equation C = 40 - M to find C: C = 40 - 30 C = 10

Answer

So, 10 cars and 30 motorcycles were repaired in the service, and a total of 100 wheels were rolled out.

I hope this helps! If you have any other questions or need further assistance, feel free to ask.