Question

Из города А в город в выехал велосипедист через 3 часа Из города А в город в выехал мотоциклист со скоростью 42 километров час через 2 часа после выезда Мотоциклист и они встретились Найдите скорость велосипедиста если расстояние между городами А и Б равно 144 км

Answer 1

42*2 = 84 км проехал мотоциклист  за 2 часа и велосипедист   2+3 =5 часов .144-84 = 60 км . 60 : 5 = 12 км в ч 

Answer 2

Problem Analysis

We are given that a cyclist and a motorcyclist start from city A and city B, respectively. The cyclist starts 3 hours before the motorcyclist, and the motorcyclist starts 2 hours after the cyclist. They meet each other, and we need to find the speed of the cyclist given that the distance between city A and city B is 144 km.

Solution

Let's assume the speed of the cyclist is x km/h. Since the cyclist starts 3 hours before the motorcyclist, the time taken by the cyclist to meet the motorcyclist is t hours. The motorcyclist starts 2 hours after the cyclist, so the time taken by the motorcyclist to meet the cyclist is t - 2 hours.

We can use the formula distance = speed × time to calculate the distance traveled by each person.

For the cyclist: distance = speed × time distance = x × t ---(1)

For the motorcyclist: distance = speed × time distance = 42 × (t - 2) ---(2)

Given that the distance between city A and city B is 144 km, we can equate the distances traveled by the cyclist and the motorcyclist: x × t = 42 × (t - 2) ---(3)

Simplifying equation (3), we get: xt = 42t - 84 xt - 42t = -84 t(x - 42) = -84 t = -84 / (x - 42) ---(4)

Substituting the value of t from equation (4) into equation (1), we can solve for x: distance = x × t 144 = x × (-84 / (x - 42)) 144(x - 42) = -84x 144x - 6048 = -84x 144x + 84x = 6048 228x = 6048 x = 6048 / 228 x = 26.53

Therefore, the speed of the cyclist is approximately 26.53 km/h.

Answer

The speed of the cyclist is approximately 26.53 km/h.