
В погоне за брошенным мячом дельфин развил скорость,которая в 5 раз больше скорости морского
котика.Кому из них потребуется меньше времени и во сколько раз чтобы проплыть 100м.?Кто из них за одну минуту проплывёт большее расстояние и во сколько раз?

Ответы на вопрос

t1\t2 = 5
Дельфину потребуется меньше времени в 5 раз.
За 1 минуту большее расстояние проплывёт дельфин.
S1 = 60·5x = 300x - путь дельфина
S2 = 60·x - путь котика
S2\S1 = 1\5
Расстояние больше в 5 раз
Удачи!!



Calculating Time and Distance for Dolphin and Seal
To calculate the time and distance for the dolphin and seal, we can use the given information that the dolphin's speed is 5 times greater than the seal's speed.
Speed of the Dolphin (D): 5 times the speed of the Seal (S)
Time to Swim 100m
The time taken by each animal to swim 100m can be calculated using the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]
Dolphin: \[ \text{Time taken by Dolphin (T\_D)} = \frac{100}{D} \]
Seal: \[ \text{Time taken by Seal (T\_S)} = \frac{100}{S} \]
Distance Covered in One Minute
The distance covered by each animal in one minute can be calculated using the formula: \[ \text{Distance} = \text{Speed} \times \text{Time} \]
Dolphin: \[ \text{Distance covered by Dolphin in 1 minute (D\_D)} = D \times 1 \]
Seal: \[ \text{Distance covered by Seal in 1 minute (D\_S)} = S \times 1 \]
Let's calculate the time and distance for the dolphin and seal using the given information.
Calculation
Given: - Speed of the Dolphin (D): 5 times the speed of the Seal (S)
Using the given information, we can calculate the time and distance for the dolphin and seal.
Time taken by Dolphin (T\_D): \[ T\_D = \frac{100}{D} \]
Time taken by Seal (T\_S): \[ T\_S = \frac{100}{S} \]
Distance covered by Dolphin in 1 minute (D\_D): \[ D\_D = D \times 1 \]
Distance covered by Seal in 1 minute (D\_S): \[ D\_S = S \times 1 \]
Let's calculate the values for \( T\_D \), \( T\_S \), \( D\_D \), and \( D\_S \) using the given information.
Results
Using the given information, we can calculate the values for \( T\_D \), \( T\_S \), \( D\_D \), and \( D\_S \).
Time taken by Dolphin (T\_D): \[ T\_D = \frac{100}{5S} \]
Time taken by Seal (T\_S): \[ T\_S = \frac{100}{S} \]
Distance covered by Dolphin in 1 minute (D\_D): \[ D\_D = 5S \]
Distance covered by Seal in 1 minute (D\_S): \[ D\_S = S \]
Conclusion
- Time taken by Dolphin (T\_D): \( T\_D = \frac{100}{5S} \) - Time taken by Seal (T\_S): \( T\_S = \frac{100}{S} \) - Distance covered by Dolphin in 1 minute (D\_D): \( D\_D = 5S \) - Distance covered by Seal in 1 minute (D\_S): \( D\_S = S \)
Based on the calculations, the time taken by the dolphin and seal to swim 100m and the distance covered by each in one minute can be determined.


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