Question

Помогите решить На факультете в среднем 29% студентов не сдают экзамен по теории вероятности. Предположим, что в группе 10 студентов. Чему равна вероятность того, что 2 студента не сдадут экзамен.

Answer 1

По формуле Бернулли
Р(2)=$C_{10}^2*0.29^2*0.71^8=45*0.0841*0.0646=0.244$

Answer 2

Calculating the Probability of 2 Students Failing the Probability Theory Exam

To calculate the probability of 2 students out of 10 failing the probability theory exam, we can use the binomial probability formula. The formula for the binomial probability is:

P(X = k) = (n choose k) * (p^k) * ((1-p)^(n-k))

Where: - n = total number of trials (in this case, the number of students) - k = number of successful trials (in this case, the number of students failing the exam) - p = probability of success on an individual trial (in this case, the probability of a student failing the exam)

Applying the Formula

Given: - n = 10 (total number of students) - k = 2 (number of students failing the exam) - p = 0.29 (probability of a student failing the exam)

We can now calculate the probability using the formula.

P(X = 2) = (10 choose 2) * (0.29^2) * ((1-0.29)^(10-2))

Calculation

Let's calculate the individual components and then the final probability.