Question

Реши задачу. Два пловца поплыли одновремино навстречу друг другу с разных концов бассейна, длина которого 110 м. Первый плыл со скорость 25 м/мин. С какой скорость плыл второй пловец,если они встретились через 2 мин ?

Answer 1

1)110-25=85
2)85•2=172
Но это не точно

Answer 2

T=2 минуты
V¹=25 м/мин.
V²=?
S=110 м.
Крч.
25*2=50 метров ( проплыл первый пловец )
110-50=60 метров ( проплыл второй пловец )
60:2=30 м/мин. ( V²/скорость второго пловца )

Answer 3

Problem Analysis

Two swimmers are swimming towards each other from opposite ends of a 110m long pool. The first swimmer is swimming at a speed of 25 m/min. We need to find the speed at which the second swimmer is swimming, given that they meet after 2 minutes.

Solution

Let's denote the speed of the second swimmer as x m/min.

When they meet, the total distance covered by both swimmers is equal to the length of the pool, which is 110m.

The first swimmer covers a distance of 25m/min * 2min = 50m.

The second swimmer covers a distance of x m/min * 2min = 2x.

The sum of their distances is equal to the length of the pool: 50m + 2x = 110m

Calculating the Speed of the Second Swimmer

To find the speed of the second swimmer, we can solve the equation: 50m + 2x = 110m

Subtracting 50m from both sides: 2x = 60m

Dividing both sides by 2: x = 30m/min

The speed of the second swimmer is 30 m/min.

Final Answer

The second swimmer was swimming at a speed of 30 m/min.