Question

Токарь изготовил детали за 8 часов,его ученик такую же партию за 12.За сколько часов они изготовят эту партию если будут работать вместе?

Answer 1

Ответ:

решение:

1/8 +1/12 = 5/24

1:5/24 = 4,8 час

ответ 4,8 час

Пошаговое объяснение:

Answer 2

Problem Analysis

We are given that a turner (tokar) produced a batch of parts in 8 hours, while his apprentice produced the same batch in 12 hours. We need to determine how long it will take for them to produce the batch if they work together.

Solution

To solve this problem, we can use the concept of work rates. The work rate of a person is defined as the amount of work they can complete in a unit of time. In this case, we can assume that the amount of work required to produce the batch of parts is the same for both the turner and the apprentice.

Let's denote the work rate of the turner as T (in parts per hour) and the work rate of the apprentice as A (in parts per hour). We are given that the turner can produce the batch in 8 hours, so we can write:

T = (Total work) / (Time taken by the turner) = 1 / 8 parts per hour Similarly, we are given that the apprentice can produce the batch in 12 hours, so we can write:

A = (Total work) / (Time taken by the apprentice) = 1 / 12 parts per hour Now, let's assume that it takes x hours for them to produce the batch together. In x hours, the turner will complete x/T parts of the batch, and the apprentice will complete x/A parts of the batch. Since they are working together, the sum of their individual contributions should be equal to the total work required to produce the batch, which is 1.

So, we can write the equation:

(x/T) + (x/A) = 1

Substituting the values of T and A, we get:

(x/ (1/8)) + (x/ (1/12)) = 1

Simplifying the equation, we get:

(8x) + (12x) = 1

Solving for x, we find:

20x = 1

x = 1/20 hours

Therefore, it will take them 1/20 hours to produce the batch if they work together.

Answer

If the turner and his apprentice work together, they will be able to produce the batch of parts in 1/20 hours.