Question

Помогите плиз!!!! Пожалуйста !!!! 1)1,5 + 8 1/5 =? 2 ) а) Найдите периметр прямоугольника ,если одна его сторона равна 35 5/6 м , а другая на 2 2/3 м меньше Б) первый рабочий может изготовить 10 деталей за 7 часов а второй 15 деталей за 8 часов . Какой рабочий быстрее изготовит 1 деталь и на сколько минут?

Answer 1

1)1,5+8 1/5=?
8 1/5=8.2
1,5+8,2=9,7
2)а)первая сторона=35 5/6м
вторая сторона= на 2 2/3м меньше
1)35 5/6-2 2/3=35 5/6- 2 4/6=33 1/6
P=(а+b)*2
P=(35 5/6+33 1/6)*2+138
б)не знаю)

Answer 2

Calculation Questions

1) 1.5 + 8 + 1/5 = ?

To calculate 1.5 + 8 + 1/5, we can add the whole numbers and the fractions separately.

1.5 + 8 = 9.5

Now, adding 9.5 and 1/5:

9.5 + 1/5 = 9.6

So, 1.5 + 8 + 1/5 = 9.6.

[[2 #1]]

Geometry Question

2) Find the perimeter of a rectangle if one of its sides is 35 5/6 m, and the other is 2 2/3 m less.

To find the perimeter of the rectangle, we can use the formula:

Perimeter = 2 * (length + width)

Given that one side is 35 5/6 m and the other is 2 2/3 m less, we can calculate the width as:

35 5/6 - 2 2/3 = 35 5/6 - 8/3 = 35 15/18 - 16/18 = 35 11/18

Now, we can calculate the perimeter:

Perimeter = 2 * (35 5/6 + 35 11/18) = 2 * (70 10/18 + 35 11/18) = 2 * (105 21/18) = 2 * 105 7/9 = 210 7/9

So, the perimeter of the rectangle is 210 7/9 meters.

Work Efficiency Question

3) The first worker can make 10 details in 7 hours, and the second worker can make 15 details in 8 hours. Which worker will make 1 detail faster and by how many minutes?

To find out which worker will make 1 detail faster and by how many minutes, we can calculate the time each worker takes to make 1 detail.

For the first worker: Time taken to make 1 detail = Total time / Number of details = 7 hours / 10 details = 0.7 hours

For the second worker: Time taken to make 1 detail = Total time / Number of details = 8 hours / 15 details ≈ 0.533 hours

Converting the time to minutes: 0.7 hours = 0.7 * 60 = 42 minutes 0.533 hours = 0.533 * 60 ≈ 32 minutes

So, the second worker will make 1 detail faster by approximately 10 minutes.

Therefore, the second worker will make 1 detail faster by approximately 10 minutes.