Question

Боря купил 4 книги. Все книги без первой стоят 42 руб., без второй - 42 руб.без третьей - 38 руб., без четвертой 36 руб. сколько стоит каждая книга?

Answer 1

Мне кажется то что нужно сделать 42+42+38+36=158 158÷4=39 (ост. 2)

Answer 2

Problem Analysis

Borya bought 4 books, and the prices of the books without the first, second, third, and fourth books are given as 42 rubles, 42 rubles, 38 rubles, and 36 rubles, respectively. We need to find the price of each book.

Solution

Let's assume the price of the first book is x rubles. Then, we can calculate the prices of the other books using the given information.

The price of the second book is also 42 rubles, so we can set up the equation: x + 42 = 42

Simplifying the equation, we find: x = 0

This means that the price of the first book is 0 rubles. However, this seems unlikely, so let's try another approach.

Let's assume the price of the first book is y rubles. Then, we can set up the following equations:

y + 42 = 42 y + 38 = 38 y + 36 = 36

Simplifying these equations, we find: y = 0

This means that the price of the first book is 0 rubles. However, this doesn't seem right either, as it would mean that all the books are free.

Let's try one more approach.

Let's assume the price of the first book is z rubles. Then, we can set up the following equations:

z + 42 = 42 z + 42 = 38 z + 42 = 36

Simplifying these equations, we find: z = -6

This means that the price of the first book is -6 rubles. However, negative prices are not possible, so this solution is also not valid.

Based on the given information, it seems that there is no consistent solution for the prices of the books. It's possible that there is missing or incorrect information in the problem statement.

Please double-check the information provided and let me know if there are any additional details or corrections.