Question

фермер собрал урожай картофеля и решил продать его на рынке. В первый день он продал 0,4 всего картофеля, во второй день 0,4 остатка, а в третий день на 1,6 т меньше чем в первый. Сколько всего картофеля было продано?

Answer 1

Ответ:

40 тонн картофеля было продано

Пошаговое объяснение:

Весь урожай составляет х тонн. Тогда:

0,4х тонн продал в первый  день

0,4(х-0,4х) = 0,4*0,6х = 0,24х тонн продал во второй  день

0,4х - 1,6 тонн продал в третий день

Составим уравнение:

0,4х + 0,24х + 0,4х - 1,6 = х

1,04х - х = 1,6

0,04х = 1,6

х = 1,6/0,04

х = 40 (тонн) картофеля было продано

Answer 2

Ответ:

40тн продано всего

Пошаговое объяснение:

Х - весь урожай

0,4х -т продано в 1 день

0,4(х-0,4х)= 0,6х ×0,4=0,24х т продано во 2 день

0,4х - 1,6 т продано в 3 день

Составим уравнение

0,4х+0,24х++0,4х-1,6=х

1,04х-х=1,6

Х=1,6:0,04=40тн продано всего

Answer 3

Problem Analysis

A farmer harvested a crop of potatoes and decided to sell them at the market. On the first day, the farmer sold 0.4 of the total potatoes. On the second day, the farmer sold 0.4 of the remaining potatoes. On the third day, the farmer sold 1.6 tons less than on the first day. We need to determine the total amount of potatoes that were sold.

Solution

To find the total amount of potatoes sold, we need to calculate the sum of the potatoes sold on each day.

Let's assume the total amount of potatoes harvested is P tons.

On the first day, the farmer sold 0.4 of the total potatoes, which is 0.4P tons.

On the second day, the farmer sold 0.4 of the remaining potatoes. The remaining potatoes after the first day's sale is (1 - 0.4)P = 0.6P tons. Therefore, the potatoes sold on the second day is 0.4 * 0.6P = 0.24P tons.

On the third day, the farmer sold 1.6 tons less than on the first day. So, the potatoes sold on the third day is (0.4P - 1.6) tons.

To find the total amount of potatoes sold, we add the potatoes sold on each day:

Total potatoes sold = potatoes sold on the first day + potatoes sold on the second day + potatoes sold on the third day

Total potatoes sold = 0.4P + 0.24P + (0.4P - 1.6)

Simplifying the equation:

Total potatoes sold = 1.04P - 1.6

Now, we need to solve for P, the total amount of potatoes harvested.

To do this, we can set up an equation using the information given:

Total potatoes sold = P

1.04P - 1.6 = P

Subtracting P from both sides:

0.04P - 1.6 = 0

Adding 1.6 to both sides:

0.04P = 1.6

Dividing both sides by 0.04:

P = 1.6 / 0.04

P = 40

Therefore, the total amount of potatoes harvested was 40 tons.

Answer

The total amount of potatoes that were sold is 40 tons.

Explanation

The farmer sold 0.4 of the total potatoes on the first day, which is 0.4 * 40 = 16 tons.

On the second day, the farmer sold 0.4 of the remaining potatoes, which is 0.4 * (40 - 16) = 0.4 * 24 = 9.6 tons.

On the third day, the farmer sold 1.6 tons less than on the first day, which is 16 - 1.6 = 14.4 tons.

Therefore, the total amount of potatoes sold is 16 + 9.6 + 14.4 = 40 tons, which matches the total amount of potatoes harvested.

Note: The sources provided do not contain relevant information for this specific problem.