Question

Коля,Дима и Саша собрали вместе 30 грибов.Дима нашёл в два раза больше грибов,чем Коля,а Коля-в 3 раза меньше,чем Саша.Сколько грибов нашёл каждый из них?.Сделай чертёж к задаче и реши её.

Answer 1

Дима - 10 грибов, Коля-5 грибов, Саша -15 грибов, потому что дима нашел в 2 раза больше чем Коля, а Коля в 3 раза меньше, чем Саша

Answer 2

Problem Analysis

We are given that Kolya, Dima, and Sasha collected a total of 30 mushrooms. Dima found twice as many mushrooms as Kolya, and Kolya found three times fewer mushrooms than Sasha. We need to determine how many mushrooms each of them found.

Solution

Let's assign variables to represent the number of mushrooms found by each person: - Let K represent the number of mushrooms found by Kolya. - Let D represent the number of mushrooms found by Dima. - Let S represent the number of mushrooms found by Sasha.

From the given information, we can form the following equations: 1. Dima found twice as many mushrooms as Kolya: D = 2K. 2. Kolya found three times fewer mushrooms than Sasha: K = S/3. 3. The total number of mushrooms found is 30: K + D + S = 30.

We can solve this system of equations to find the values of K, D, and S.

Solving the Equations

Substituting equation 2 into equation 1, we get: D = 2(S/3).

Substituting the values of D and K into equation 3, we get: S/3 + 2(S/3) + S = 30.

Simplifying the equation: S/3 + 2S/3 + S = 30, 4S/3 + S = 30, 7S/3 = 30.

Multiplying both sides of the equation by 3/7, we get: S = (30 * 3) / 7.

Using this value of S, we can find the values of K and D: K = S/3, D = 2K.

Calculation

Let's calculate the values of S, K, and D using the equations above.

S = (30 * 3) / 7, K = S/3, D = 2K.

Using a calculator, we find: S ≈ 12.857, K ≈ 4.286, D ≈ 8.571.

Answer

Therefore, Kolya found approximately 4 mushrooms, Dima found approximately 8 mushrooms, and Sasha found approximately 13 mushrooms.

Diagram

Here is a diagram representing the problem:

Kolya (K)   Dima (D)   Sasha (S)
   4           8          13

Please note that the values are approximate due to rounding.

I hope this helps! Let me know if you have any further questions.