Question

X^2-4x-5/x^2-3x-4=0 помогите пожалуйста

Answer 1

Х²-4х-5 / х²-3-4=(x-5)(x+1)/(x-4)(x+1)=(x-5)/(x-4)

х²-4х-5=0
а=1; б= -4; с= -5
D=б²-4ас=16-4×1×(-5)=16+20=36=6²
х= -б+(-)корень из D /2а
х1= 4+6/2=10/2=5
х2= 4-6/2=-2/2=-1
x²-4x-5=(x-5)(x+1)

х²-3x-4=0
D=9+16=25=5²
x1=3+5/2=8/2=4
x2=3-5/2=-2/2=-1
x²-3x-4=(x-4)(x+1)

Answer 2

Solving the Equation x^2-4x-5/x^2-3x-4=0

To solve the equation x^2-4x-5/x^2-3x-4=0, we can follow these steps:

1. Factorize the denominators and simplify the equation. 2. Solve for the values of x that satisfy the equation.

Step 1: Factorize the Denominators and Simplify the Equation

The given equation is x^2-4x-5/x^2-3x-4=0. To simplify this equation, we can factorize the denominators and then simplify the expression.

The factorization of the denominators is as follows: - For x^2-3x-4, the factorization is (x-4)(x+1). - For x^2-4x-5, the factorization is (x-5)(x+1).

Now, the equation becomes (x-5)(x+1)/(x-4)(x+1)=0.

Step 2: Solve for the Values of x

To solve for the values of x, we can set each factor equal to zero and solve for x.

Setting (x-5)=0 gives x=5. Setting (x+1)=0 gives x=-1. Setting (x-4)=0 gives x=4.

Therefore, the solutions for the equation x^2-4x-5/x^2-3x-4=0 are x=5, x=-1, and x=4.

In summary, the solutions for the given equation x^2-4x-5/x^2-3x-4=0 are x=5, x=-1, and x=4.