Question

Колхоз посеял кукурузу на 4-х частках. Площади первых двух участков относились между собой, как 1/3 : 0,2. Площадь третьего участка составляет 29 1/6 % всего посева кукурузы, а площадь 4-го - 7/40 площади всего посева кукурузы. Сколько га кукурузы было посеяно в колхозе, если 3-ий участок на 20 га меньше, чем 1ый?

Answer 1

29 1/6=175/6%=175/6:100=175/6*1/100=7/6*1/4=7/24 в долях числа
1/3х+0,2х+7/24у+7/40у=у умножим на 120
40х+24х+35у+21у=120у
64х+56у=120у
64х=64у
х=у

1/3х=7/24у+20 умножим на 24
8х=7у+480
х=7у/8+60

у=7у/8+60
у-7у/8=60
1у/8=60
у=60:1/8=60*8=480 га-посеяли всего

Answer 2

Calculation of Corn Planting Area in the Collective Farm

To calculate the total area of corn planted in the collective farm, we need to analyze the information provided about the four plots.

Let's break down the given information:

- The areas of the first two plots are in a ratio of 1/3 to 0.2. - The area of the third plot is 29 1/6% of the total corn planting area. - The area of the fourth plot is 7/40 of the total corn planting area. - The third plot is 20 hectares smaller than the first plot.

To solve this problem, we can assign variables to the areas of the plots and create equations based on the given information.

Let's assume: - The area of the first plot is x hectares. - The area of the second plot is y hectares. - The area of the third plot is z hectares. - The area of the fourth plot is w hectares.

Based on the given information, we can create the following equations:

1. The areas of the first two plots are in a ratio of 1/3 to 0.2: - x/y = 1/3 - x = (1/3)y

2. The area of the third plot is 29 1/6% of the total corn planting area: - z = (29 1/6/100)(x + y + z + w) - z = (29 1/6/100)(x + y + z + 7/40(x + y + z + w))

3. The area of the fourth plot is 7/40 of the total corn planting area: - w = (7/40)(x + y + z + w)

4. The third plot is 20 hectares smaller than the first plot: - z = x - 20

Now, we can solve these equations to find the values of x, y, z, and w.

Let's substitute equation 1 into equation 2: - z = (29 1/6/100)(x + y + z + 7/40(x + y + z + w)) - z = (29 1/6/100)(4/3y + z + 7/40(4/3y + z + w))

Simplifying the equation: - z = (29 1/6/100)(4/3y + z + 7/30y + 7/40z + 7/40w) - z = (29 1/6/100)(4/3y + 7/30y + z + 7/40z + 7/40w) - z = (29 1/6/100)(59/30y + 47/40z + 7/40w)

Substituting equation 4 into the simplified equation: - x - 20 = (29 1/6/100)(59/30y + 47/40z + 7/40w)

Now, we have three equations with three variables (x, y, and w). We can solve these equations simultaneously to find the values of x, y, z, and w.

Unfortunately, the given information does not provide enough data to solve the problem. We need additional information or equations to determine the values of x, y, z, and w.

If you have any additional information or equations, please provide them, and I will be happy to help you solve the problem.